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2.08x^2-5.20x-3.12=0
We add all the numbers together, and all the variables
2.08x^2-5.2x-3.12=0
a = 2.08; b = -5.2; c = -3.12;
Δ = b2-4ac
Δ = -5.22-4·2.08·(-3.12)
Δ = 52.9984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.2)-\sqrt{52.9984}}{2*2.08}=\frac{5.2-\sqrt{52.9984}}{4.16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.2)+\sqrt{52.9984}}{2*2.08}=\frac{5.2+\sqrt{52.9984}}{4.16} $
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